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SYS_FileManager.getProjectFileByProjectUuid() method

This API is provided as a beta preview for developers and may change based on feedback that we receive. Do not use this API in a production environment.

Use project UUID get project file

Signature

function getProjectFileByProjectUuid(
	projectUuid: string,
	fileName?: string,
	password?: string,
	fileType?: 'epro' | 'epro2',
): Promise<File | undefined>;

Parameters

Parameter	Type	Description
projectUuid	string	Project UUID
fileName	string	(Optional) File name
password	string	(Optional) Encrypted password
fileType	'epro' | 'epro2'	(Optional) File format

Returns

Promise<File | undefined>

Project file data, undefined indicates that it is currently not open project or data retrieval failed

Remarks

You can use SYS_FileSystem.saveFile() API export the file to the local file system

Note: This API requires the **Project Management > Download Project** permission. Calling it without permission will always throw Error

Example

// 1. 获取当前工程的 UUID
const projectInfo = await eda.dmt_Project.getCurrentProjectInfo();

// 2. 按工程 UUID 下载工程文件（文件名自动带上 epro2 扩展名）
const projectFile = await eda.sys_FileManager.getProjectFileByProjectUuid(projectInfo.uuid, '嘉立创示例_按UUID导出');

// 3. 输出文件信息（size 单位为字节）
console.log('文件名：', projectFile.name);
console.log('文件大小：', projectFile.size);